Oracle sql online test

Leave a Comment / By techgoeasy / September 5, 2018

Oracle SQL is the widely used in various Products. Having a knowledge in Oracle SQL is plus point.

This Oracle sql online test check the understanding on various topics like Oracle table, Oracle view ,constraints, type of index, sequences, subqueries , oracle joins ,materialized view, primary key constraints , single row function ,sql queries and many more

The below test is randomized sql test and select 15 questions from the set of many questions,so each time you try to attempt it, you will get different questions in different order and option would also be in different order, So it will be fun practicing with this tool. You can try as many times as you want till you feel comfortable about it

Instructions for online test

1.This quiz consists of 15 questions .It is recommended to complete the test in 30 min
2. It consists both single choice and more than one choice questions to test your knowledge
3. You can press the submit button at the end of your test and get the final score
4.You will also get the know the correct choice after you finished the test.

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1. You need to test if the current fetch within a PL/SQL loop was successful. Which cursor attribute is needed to accomplish this task?

A cursor attribute cannot be used within a PL/SQL loop.

SQLROWCOUNT

SQL%ISOPEN

SQL%FOUND

Question 1 of 15

2. The emp table contains these columns:
Last_name Varchar2 (25)
First_name Varchar2 (25)
Salary Number7, 2
You need to display the names of employees on more than an average salary of all
employees. Evaluate the SQL statement.
SELECT, LAST_NAME, FIRST_NAME from emp where salary< avg(salary);

Which change should you make to achieve the desired results?

Move the function to the select clause and add a group clause.

Use a sub query in the where clause to compare the average salary value.

Move the function to the select clause and add a group by clause and a having clause.

Change the function in the Where clause.

Question 2 of 15

3. You have decided to permanently remove all the data from the student_masters table and you need the table structure in the future. Which single command performs this?

TRUNCATE TABLE student_masters KEEP STRUCTURE;

DELETE* FROM student_masters KEEP STRUCTURE.

DROP TABLE student_masters;

TRUNCATE TABLE student_masters;

DELETE* FROM student_masters;

Question 3 of 15

4. A group function produces ______.

A group of results from one row.

One result from many rows per group.

Many results from many rows per group.

One result from each row in a table.

Question 4 of 15

5. You must permanently remove all data from the sales_data table, but will need the table structure in the future. What single command should be issued?

TRUNCATE TABLE sales_data

TRUNCATE TABLE sales_data KEEP STRUCTURE;

DROP TABLE sales_data

DELETE FROM sales_data

Question 5 of 15

6. Examine the WORKER table below:

NAME NULL TYPE
WORKER ID NOT NULL NUMBER(3)
NAME NOT NULL VARCHAR2(25)
PHONE NOT NULL VARCHAR2(9)
ADDRESS VARCHAR2(50)
POSITION UPDATE

There are hundreds of records in the EMPLOYEE TABLE. You need to modify the phone column to hold only number values. Which statement will modify the data type appropriately?

A VARCHAR2 data type cannot be changed to a NUMBER data type for a column.

ALTER TABLE worker MODIFY phone NUMBER(9)

ALTER WORKER table MODIFY COLUMN phone NUMBER(9)

The data type of a column cannot be modified if there is data in the column.

Question 6 of 15

7. You need to analyze how long your orders to be shipped from the date that the order is placed. To do this you must create a report that displays the customer number, date order, date shipped and the number of months in whole numbers from the time the order is placed to the time the order is shipped. Which statement produces the
required results?

SELECT custid, orderate, shipdate,ROUND OFF (shipdate-orderate) “Time Taken” FROM order;

SELECT custid, orderate, shipdate, ROUND(DAYS_BETWEEN(shipdate,orderate))/30 FROM order;

SELECT custid, orderate, shipdate, MONTHS_BETWEEN (shipdate,orderate) “Time Taken” FROM order;

SELECT custid, orderate, shipdate, ROUND(MONTHS_BETWEEN(shipdate,orderate)) “Time Taken”FROM order;

Question 7 of 15

8. Examine the following command:

CREATE TABLE pay_master
(employee-id Number(9)
CONSTRAINT pay-pk PRIMARY KEY,
2000-pay NUMBER(8,2)
manager-name VARCHAR2(25)
CONSTRAINT mgr-name-nn. NOT NULL,
pay-96 NUMBER(8,2));

Which two lines of this command will return an error?

Second

Fifth

First

Fourth

Sixth

Third

Question 8 of 15

9. What should be done after each fetch statement in a PL/SQL block?

Initialize the loop.

Close the cursor.

Open the cursor.

Test for rows using the cursor attribute.

Question 9 of 15

10. What command should be used to execute a script file named create_table.sql from the SQL Plus environment?

EXECUTE create_table

START create_table

RUN create_table

GET create_table

Question 10 of 15

11. How would you add a foreign key constraint on the dept_no column in the EMP table. Referring to the ID column in the DEPT table?

Use the ALTER TABLE command with the MODIFY clause on the DEPT table.

Use the ALTER TABLE command with the MODIFY clause on the EMP table.

Use the ALTER TABLE command with the ADD clause on the EMP table.

Use the ALTER TABLE command with the ADD clause in the DEPT table.

This task cannot be accomplished.

Question 11 of 15

12. You query a database with the following command:

SELECT dept_no, AVG (MONTHS_BETWEEN (SYSDATE, hire_date)) FROM worker_company
WHERE AVG (MONTHS_BETWEEN (SYSDATE, hire_date)) > 60
GROUP BY dept_no
ORDER BY AVG (MONTHS_BETWEEN (SYSDATE, hire_date) )

Where does the statement cause an error?

A group function cannot contain a single row function.

An ORDER BY clause cannot contain a group function.

A SELECT clause cannot contain a group function.

A WHERE clause cannot be used to restrict groups.

Question 12 of 15

13. The emp table contains these columns:
FIRST-NAME VARCHER2(25)
COMISSION NUMBER(3,2)
Evaluate this SQL statement
SELECT first-name,commission FROM emp WHERE commission= (SELECT comission FROM emp WHERE UPPER(first-name)= ‘smith’)
Which statement will cause this statement to fail?

The first name values in the data base are in the lower case.

smith has a null commission resolution.

There is no employee with the first name smith.

smith has a zero commission resolution.

Question 13 of 15

14. You need to create a report to display the ship date and order totals of your order table. If the order has not been shipped your report must display not shipped. If the total is not available your report must say not available. In the order table the ship date column has a data type of date the total column has a data type of number. Which statement do you use to create this report?

Select order, NVL (shipdate ‘Not shipped’),NVL (total, “Not available”) FROM order;

Select order, shipdate “Not shipped”,total “Not available” FROM order;

Select order, TO_CHAR (shipdate, ‘Not shipped’) TO_CHAR (total, ‘Not available’) FROM order;

Select order, NVL (TO_CHAR (shipdate), ‘Not shipped’),NVL (TO_CHAR (total), ‘Not available’) FROM order;

Question 14 of 15

15. You have been instructed to create a report that shows different jobs in each division within your company. No duplicate roles can be displayed. Which of the following SELECT statements should be used?

CREATE report DISPLAY divisionno, job

SELECT no duplicate divisionno, job FROM worker;

SELECT distinct divisionno, job FROM worker;

SELECT divisionno, job FROM worker;

Question 15 of 15

I hope you like this Oracle sql online test and it helps in your examination preparation. Best of Luck for the Oracle certification Examination. Please do provide feedback on it. We will also be adding more quizes and questions in future.

Happy Learning!!!!

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