Oracle sql online test for Certification

Oracle SQL is the widely used in various Products. Having a knowledge in Oracle SQL is plus point.

This Oracle sql online test check the understanding on various topics like Oracle table, Oracle view ,constraints, type of index, sequences, subqueries , oracle joins ,materialized view, primary key constraints , single row function ,sql queries and many more

The below test is randomized sql test and select 15 questions from the set of many questions,so each time you try to attempt it, you will get different questions in different order and option would also be in different order, So it will be fun practicing with this tool. You can try as many times as you want till you feel comfortable about it

Instructions for online test

1.This quiz consists of 15 questions .It is recommended to complete the test in 30 min
2. It consists both single choice and more than one choice questions to test your knowledge
3. You can press the submit button at the end of your test and get the final score
4.You will also get the know the correct choice after you finished the test.

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1. You must permanently remove all data from the sales_data table, but will need the table structure in the future. What single command should be issued?

DELETE FROM sales_data

TRUNCATE TABLE sales_data KEEP STRUCTURE;

DROP TABLE sales_data

TRUNCATE TABLE sales_data

Question 1 of 15

2. You need to analyze how long your orders to be shipped from the date that the order is placed. To do this you must create a report that displays the customer number, date order, date shipped and the number of months in whole numbers from the time the order is placed to the time the order is shipped. Which statement produces the
required results?

SELECT custid, orderate, shipdate,ROUND OFF (shipdate-orderate) “Time Taken” FROM order;

SELECT custid, orderate, shipdate, MONTHS_BETWEEN (shipdate,orderate) “Time Taken” FROM order;

SELECT custid, orderate, shipdate, ROUND(MONTHS_BETWEEN(shipdate,orderate)) “Time Taken”FROM order;

SELECT custid, orderate, shipdate, ROUND(DAYS_BETWEEN(shipdate,orderate))/30 FROM order;

Question 2 of 15

3. How would you add a foreign key constraint on the dept_no column in the EMP table. Referring to the ID column in the DEPT table?

Use the ALTER TABLE command with the ADD clause on the EMP table.

Use the ALTER TABLE command with the ADD clause in the DEPT table.

Use the ALTER TABLE command with the MODIFY clause on the EMP table.

Use the ALTER TABLE command with the MODIFY clause on the DEPT table.

This task cannot be accomplished.

Question 3 of 15

4. Examine the structure of student_masters table:
Name Null Type
STU ID NOT NULL NUMBER(3)
NAME VARCHER2(25)
ADDRESS VARCHER2(50)
GRADUATION DATE
Currently the table is empty. You have decided that null values should not be allowed for the NAME column. Which statement restricts NULL values from being entered into column?

ALTER TABLE student_masters MODIFY(name varcher2(25) NOT NULL);

ALTER TABLE student_masters ADD CONSTRAINT NOT NULL (name);

ALTER TABLE student_masters MODIFY CONSTRAINT name(NOT NULL);

ALTER TABLE student_masters ADD CONSTRAINT name(NOT NULL);

Question 4 of 15

5. You query a database with the following command:

SELECT dept_no, AVG (MONTHS_BETWEEN (SYSDATE, hire_date)) FROM worker_company
WHERE AVG (MONTHS_BETWEEN (SYSDATE, hire_date)) > 60
GROUP BY dept_no
ORDER BY AVG (MONTHS_BETWEEN (SYSDATE, hire_date) )

Where does the statement cause an error?

A WHERE clause cannot be used to restrict groups.

A group function cannot contain a single row function.

A SELECT clause cannot contain a group function.

An ORDER BY clause cannot contain a group function.

Question 5 of 15

6. The emp table contains these columns:
Last_name Varchar2 (25)
First_name Varchar2 (25)
Salary Number7, 2
You need to display the names of employees on more than an average salary of all
employees. Evaluate the SQL statement.
SELECT, LAST_NAME, FIRST_NAME from emp where salary< avg(salary);

Which change should you make to achieve the desired results?

Use a sub query in the where clause to compare the average salary value.

Move the function to the select clause and add a group by clause and a having clause.

Change the function in the Where clause.

Move the function to the select clause and add a group clause.

Question 6 of 15

7. You need to store currency data and you know that data will always have two digits to the right of the decimal points. However the number of digits to the left of the decimal place will vary greatly. Which data type would be most appropriate to store the data?

NUMBER

NUMBER(T)

VARCHAR

CHAR

Question 7 of 15

8. What command should be used to execute a script file named create_table.sql from the SQL Plus environment?

EXECUTE create_table

START create_table

RUN create_table

GET create_table

Question 8 of 15

9. You have been instructed to create a report that shows different jobs in each division within your company. No duplicate roles can be displayed. Which of the following SELECT statements should be used?

SELECT distinct divisionno, job FROM worker;

SELECT no duplicate divisionno, job FROM worker;

CREATE report DISPLAY divisionno, job

SELECT divisionno, job FROM worker;

Question 9 of 15

10. Your company will be granting workers a $150 salary increase. You need to evaluate results of the increase from the worker table prior to the actual modification. You do not want to store in the results in the current database. Which of the following is untrue?

An arithmetic expression must be added that invokes the salary increment in the SET section of the upgrade clause.

A column must be added to the worker table.

An arithmetic expression must be added that invokes the salary increment in the SELECT clause of the SELECT statement.

An arithmetic expression must be added that invokes the salary increment in the UPDATE clause of the SELECT statement.

Question 10 of 15

11. What should be done after each fetch statement in a PL/SQL block?

Open the cursor.

Initialize the loop.

Close the cursor.

Test for rows using the cursor attribute.

Question 11 of 15

12. The emp table contains these columns:
FIRST-NAME VARCHER2(25)
COMISSION NUMBER(3,2)
Evaluate this SQL statement
SELECT first-name,commission FROM emp WHERE commission= (SELECT comission FROM emp WHERE UPPER(first-name)= ‘smith’)
Which statement will cause this statement to fail?

smith has a zero commission resolution.

smith has a null commission resolution.

There is no employee with the first name smith.

The first name values in the data base are in the lower case.

Question 12 of 15

13. You create the sal table with this command

CREATE TABLE sal (purchase-no NUMBER(9)
CONSTRAINT sale-purchase-no-pk PRIMARY KEY,
costumer-id NUMBER(9) CONSTRAINT sale-customer-id-nl NOT NULL);

Which index or indexes are created for this table?

No indexes are created for this table.

An index is created for the customer_no column.

An index is created for purchase_no column.

An index is created for each column.

Question 13 of 15

14. A group function produces ______.

One result from each row in a table.

One result from many rows per group.

Many results from many rows per group.

A group of results from one row.

Question 14 of 15

15. You want of display the details of all employees whose last names is john. But you are not sure in which case last names are stored. Which statement will list all the employees whose last name is john?

Select last name, first name FROM emp WHERE last name=UPPER (‘john’);

Select last name, first name. FROM emp WHERE LOWER (last name)= ‘john’;

Select last name, first nam FROM emp WHERE last name= ‘john’;

Select last name, first name FROM emp WHERE UPPER (last name)= ‘john’;

Question 15 of 15

I hope you like this Oracle sql online test and it helps in your examination preparation. Best of Luck for the Oracle certification Examination. Please do provide feedback on it. We will also be adding more quizes and questions in future.

Happy Learning!!!!

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